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2221011040433 is a prime number
BaseRepresentation
bin100000010100011110100…
…100101111100010110001
321212022211002002222110012
4200110132210233202301
5242342112311243213
64420152434344305
7316314503231513
oct40243644574261
97768732088405
102221011040433
11786a1a915709
122ba54412b095
13131595862643
14796d7239bb3
153cb90d304a8
hex2051e92f8b1

2221011040433 has 2 divisors, whose sum is σ = 2221011040434. Its totient is φ = 2221011040432.

The previous prime is 2221011040399. The next prime is 2221011040447. The reversal of 2221011040433 is 3340401101222.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2176250444944 + 44760595489 = 1475212^2 + 211567^2 .

It is a cyclic number.

It is not a de Polignac number, because 2221011040433 - 210 = 2221011039409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2221011040399 and 2221011040408.

It is not a weakly prime, because it can be changed into another prime (2221011042433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110505520216 + 1110505520217.

It is an arithmetic number, because the mean of its divisors is an integer number (1110505520217).

Almost surely, 22221011040433 is an apocalyptic number.

It is an amenable number.

2221011040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2221011040433 is an equidigital number, since it uses as much as digits as its factorization.

2221011040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 2221011040433 its reverse (3340401101222), we get a palindrome (5561412141655).

The spelling of 2221011040433 in words is "two trillion, two hundred twenty-one billion, eleven million, forty thousand, four hundred thirty-three".