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222113122129777 is a prime number
BaseRepresentation
bin110010100000001010111101…
…101111101001011101110001
31002010102210210101012000110111
4302200022331233221131301
5213103100133231123102
62104221205404301321
764533100140152224
oct6240127557513561
91063383711160414
10222113122129777
1164854711a6861a
1220ab3017241841
1396c22400a9838
143cbc49242d5bb
151aa2a13165cd7
hexca02bdbe9771

222113122129777 has 2 divisors, whose sum is σ = 222113122129778. Its totient is φ = 222113122129776.

The previous prime is 222113122129741. The next prime is 222113122129807. The reversal of 222113122129777 is 777921221311222.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115751110395361 + 106362011734416 = 10758769^2 + 10313196^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-222113122129777 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 222113122129777.

It is not a weakly prime, because it can be changed into another prime (222113122129727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111056561064888 + 111056561064889.

It is an arithmetic number, because the mean of its divisors is an integer number (111056561064889).

Almost surely, 2222113122129777 is an apocalyptic number.

It is an amenable number.

222113122129777 is a deficient number, since it is larger than the sum of its proper divisors (1).

222113122129777 is an equidigital number, since it uses as much as digits as its factorization.

222113122129777 is an evil number, because the sum of its binary digits is even.

The product of its digits is 592704, while the sum is 49.

The spelling of 222113122129777 in words is "two hundred twenty-two trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred twenty-nine thousand, seven hundred seventy-seven".