Base | Representation |
---|---|
bin | 1010000110011111100001… |
… | …00000110001111000110011 |
3 | 2220122120102211121112101121 |
4 | 11003033300200301320303 |
5 | 10402420330104344103 |
6 | 115124353150243111 |
7 | 4451600361145210 |
oct | 503176040617063 |
9 | 86576384545347 |
10 | 22213311012403 |
11 | 7094680a6a715 |
12 | 25a9108ab6497 |
13 | c519247c1374 |
14 | 56b1b6996b07 |
15 | 287c44bc16bd |
hex | 1433f0831e33 |
22213311012403 has 64 divisors (see below), whose sum is σ = 26732582231040. Its totient is φ = 18055764131328.
The previous prime is 22213311012391. The next prime is 22213311012499. The reversal of 22213311012403 is 30421011331222.
It is not a de Polignac number, because 22213311012403 - 25 = 22213311012371 is a prime.
It is a super-3 number, since 3×222133110124033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (22211311012403) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8205876376 + ... + 8205879082.
It is an arithmetic number, because the mean of its divisors is an integer number (417696597360).
Almost surely, 222213311012403 is an apocalyptic number.
22213311012403 is a deficient number, since it is larger than the sum of its proper divisors (4519271218637).
22213311012403 is a wasteful number, since it uses less digits than its factorization.
22213311012403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4364.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 22213311012403 its reverse (30421011331222), we get a palindrome (52634322343625).
The spelling of 22213311012403 in words is "twenty-two trillion, two hundred thirteen billion, three hundred eleven million, twelve thousand, four hundred three".
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