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2223112433 is a prime number
BaseRepresentation
bin1000010010000010…
…0000000011110001
312201221011210221112
42010200200003301
514023104044213
61004333003105
7106043100233
oct20440400361
95657153845
102223112433
11a40986303
12520623495
13295764659
14171376253
15d0284ea8
hex848200f1

2223112433 has 2 divisors, whose sum is σ = 2223112434. Its totient is φ = 2223112432.

The previous prime is 2223112417. The next prime is 2223112447. The reversal of 2223112433 is 3342113222.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2001936049 + 221176384 = 44743^2 + 14872^2 .

It is a cyclic number.

It is not a de Polignac number, because 2223112433 - 24 = 2223112417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2223112399 and 2223112408.

It is not a weakly prime, because it can be changed into another prime (2223112483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1111556216 + 1111556217.

It is an arithmetic number, because the mean of its divisors is an integer number (1111556217).

Almost surely, 22223112433 is an apocalyptic number.

It is an amenable number.

2223112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2223112433 is an equidigital number, since it uses as much as digits as its factorization.

2223112433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 23.

The square root of 2223112433 is about 47149.8932448420. The cubic root of 2223112433 is about 1305.1301099949.

Adding to 2223112433 its reverse (3342113222), we get a palindrome (5565225655).

The spelling of 2223112433 in words is "two billion, two hundred twenty-three million, one hundred twelve thousand, four hundred thirty-three".