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2223414113002 = 21111707056501
BaseRepresentation
bin100000010110101101110…
…011101111001011101010
321212120000112220201021221
4200112231303233023222
5242412023003104002
64421231120452254
7316431163063135
oct40265563571352
97776015821257
102223414113002
11787a433366a5
122baab4a7a08a
13131889685984
147988445921c
153cc81cb1c37
hex205adcef2ea

2223414113002 has 4 divisors (see below), whose sum is σ = 3335121169506. Its totient is φ = 1111707056500.

The previous prime is 2223414112957. The next prime is 2223414113077. The reversal of 2223414113002 is 2003114143222.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2221438221601 + 1975891401 = 1490449^2 + 44451^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555853528249 + ... + 555853528252.

Almost surely, 22223414113002 is an apocalyptic number.

2223414113002 is a deficient number, since it is larger than the sum of its proper divisors (1111707056504).

2223414113002 is a wasteful number, since it uses less digits than its factorization.

2223414113002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1111707056503.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2223414113002 its reverse (2003114143222), we get a palindrome (4226528256224).

The spelling of 2223414113002 in words is "two trillion, two hundred twenty-three billion, four hundred fourteen million, one hundred thirteen thousand, two".

Divisors: 1 2 1111707056501 2223414113002