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22240054141 = 84431263411
BaseRepresentation
bin10100101101100111…
…000100101101111101
32010101221120210211221
4110231213010231331
5331021423213031
614114505313341
71415062224664
oct245547045575
963357523757
1022240054141
119482a26938
124388195851
1321357c1666
14110d9cbddb
158a274aa11
hex52d9c4b7d

22240054141 has 4 divisors (see below), whose sum is σ = 22240401984. Its totient is φ = 22239706300.

The previous prime is 22240054121. The next prime is 22240054163. The reversal of 22240054141 is 14145004222.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22240054141 - 27 = 22240054013 is a prime.

It is a super-2 number, since 2×222400541412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22240054121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47275 + ... + 216136.

It is an arithmetic number, because the mean of its divisors is an integer number (5560100496).

Almost surely, 222240054141 is an apocalyptic number.

It is an amenable number.

22240054141 is a deficient number, since it is larger than the sum of its proper divisors (347843).

22240054141 is an equidigital number, since it uses as much as digits as its factorization.

22240054141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347842.

The product of its (nonzero) digits is 2560, while the sum is 25.

Adding to 22240054141 its reverse (14145004222), we get a palindrome (36385058363).

The spelling of 22240054141 in words is "twenty-two billion, two hundred forty million, fifty-four thousand, one hundred forty-one".

Divisors: 1 84431 263411 22240054141