Base | Representation |
---|---|
bin | 1010000111010101010101… |
… | …00000001001010001110001 |
3 | 2220202100000020121201211201 |
4 | 11003222222200021101301 |
5 | 10403404012002241032 |
6 | 115145532015411201 |
7 | 4453642323612343 |
oct | 503525240112161 |
9 | 86670006551751 |
10 | 22242201212017 |
11 | 70a5956805246 |
12 | 25b2830223b01 |
13 | c54579c83a37 |
14 | 56c757871293 |
15 | 28888617a8e7 |
hex | 143aaa809471 |
22242201212017 has 2 divisors, whose sum is σ = 22242201212018. Its totient is φ = 22242201212016.
The previous prime is 22242201211963. The next prime is 22242201212047. The reversal of 22242201212017 is 71021210224222.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21694765479696 + 547435732321 = 4657764^2 + 739889^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22242201212017 is a prime.
It is not a weakly prime, because it can be changed into another prime (22242201212047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11121100606008 + 11121100606009.
It is an arithmetic number, because the mean of its divisors is an integer number (11121100606009).
Almost surely, 222242201212017 is an apocalyptic number.
It is an amenable number.
22242201212017 is a deficient number, since it is larger than the sum of its proper divisors (1).
22242201212017 is an equidigital number, since it uses as much as digits as its factorization.
22242201212017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3584, while the sum is 28.
Adding to 22242201212017 its reverse (71021210224222), we get a palindrome (93263411436239).
The spelling of 22242201212017 in words is "twenty-two trillion, two hundred forty-two billion, two hundred one million, two hundred twelve thousand, seventeen".
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