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2224434029953 is a prime number
BaseRepresentation
bin100000010111101010100…
…110011010010110000001
321212122122122001212022211
4200113222212122112001
5242421120102424303
64421520233102121
7316465356166012
oct40275246322601
97778578055284
102224434029953
11788417023373
122bb13a557941
131319bca77525
147993daad009
153cce15c966d
hex205ea99a581

2224434029953 has 2 divisors, whose sum is σ = 2224434029954. Its totient is φ = 2224434029952.

The previous prime is 2224434029947. The next prime is 2224434030053. The reversal of 2224434029953 is 3599204344222.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2221122257649 + 3311772304 = 1490343^2 + 57548^2 .

It is a cyclic number.

It is not a de Polignac number, because 2224434029953 - 229 = 2223897159041 is a prime.

It is a super-2 number, since 2×22244340299532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2224434029897 and 2224434029906.

It is not a weakly prime, because it can be changed into another prime (2224434729953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1112217014976 + 1112217014977.

It is an arithmetic number, because the mean of its divisors is an integer number (1112217014977).

Almost surely, 22224434029953 is an apocalyptic number.

It is an amenable number.

2224434029953 is a deficient number, since it is larger than the sum of its proper divisors (1).

2224434029953 is an equidigital number, since it uses as much as digits as its factorization.

2224434029953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3732480, while the sum is 49.

The spelling of 2224434029953 in words is "two trillion, two hundred twenty-four billion, four hundred thirty-four million, twenty-nine thousand, nine hundred fifty-three".