Base | Representation |
---|---|
bin | 1100111111001000001… |
… | …0010001001101011011 |
3 | 210022212111120011022001 |
4 | 3033302002101031123 |
5 | 12123404111410042 |
6 | 250254221141431 |
7 | 22055503551631 |
oct | 3176202211533 |
9 | 708774504261 |
10 | 223104013147 |
11 | 86688443244 |
12 | 372a50ba877 |
13 | 18066ac8682 |
14 | ab26727351 |
15 | 5c0b97cbb7 |
hex | 33f209135b |
223104013147 has 2 divisors, whose sum is σ = 223104013148. Its totient is φ = 223104013146.
The previous prime is 223104013133. The next prime is 223104013163. The reversal of 223104013147 is 741310401322.
223104013147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-223104013147 is a prime.
It is a super-3 number, since 3×2231040131473 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (223104016147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111552006573 + 111552006574.
It is an arithmetic number, because the mean of its divisors is an integer number (111552006574).
Almost surely, 2223104013147 is an apocalyptic number.
223104013147 is a deficient number, since it is larger than the sum of its proper divisors (1).
223104013147 is an equidigital number, since it uses as much as digits as its factorization.
223104013147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 223104013147 its reverse (741310401322), we get a palindrome (964414414469).
The spelling of 223104013147 in words is "two hundred twenty-three billion, one hundred four million, thirteen thousand, one hundred forty-seven".
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