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22311121221049 is a prime number
BaseRepresentation
bin1010001001010101101100…
…11101000111010110111001
32220222220220101202221121211
411010222312131013112321
510411021134013033144
6115241330530403121
74461632245203313
oct504526635072671
986886811687554
1022311121221049
1171221033090a1
1226040654304a1
13c5ac11734c7b
14571c14c767b3
1528a56ba59034
hex144ab67475b9

22311121221049 has 2 divisors, whose sum is σ = 22311121221050. Its totient is φ = 22311121221048.

The previous prime is 22311121220989. The next prime is 22311121221091. The reversal of 22311121221049 is 94012212111322.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21990659936400 + 320461284649 = 4689420^2 + 566093^2 .

It is a cyclic number.

It is not a de Polignac number, because 22311121221049 - 213 = 22311121212857 is a prime.

It is a super-3 number, since 3×223111212210493 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 22311121221049.

It is not a weakly prime, because it can be changed into another prime (22311121201049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11155560610524 + 11155560610525.

It is an arithmetic number, because the mean of its divisors is an integer number (11155560610525).

Almost surely, 222311121221049 is an apocalyptic number.

It is an amenable number.

22311121221049 is a deficient number, since it is larger than the sum of its proper divisors (1).

22311121221049 is an equidigital number, since it uses as much as digits as its factorization.

22311121221049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 31.

The spelling of 22311121221049 in words is "twenty-two trillion, three hundred eleven billion, one hundred twenty-one million, two hundred twenty-one thousand, forty-nine".