Base | Representation |
---|---|
bin | 100000011101111110011… |
… | …110011110000111000001 |
3 | 21220022010212010221021102 |
4 | 200131332132132013001 |
5 | 243024004221142424 |
6 | 4425000444304145 |
7 | 320125314411662 |
oct | 40357636360701 |
9 | 7808125127242 |
10 | 2231209943489 |
11 | 79028393350a |
12 | 30050b842055 |
13 | 13252c811a17 |
14 | 79dc3977369 |
15 | 3d08b3cc7ae |
hex | 2077e79e1c1 |
2231209943489 has 2 divisors, whose sum is σ = 2231209943490. Its totient is φ = 2231209943488.
The previous prime is 2231209943447. The next prime is 2231209943497. The reversal of 2231209943489 is 9843499021322.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2098282617025 + 132927326464 = 1448545^2 + 364592^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2231209943489 is a prime.
It is a super-3 number, since 3×22312099434893 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2231209913489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1115604971744 + 1115604971745.
It is an arithmetic number, because the mean of its divisors is an integer number (1115604971745).
Almost surely, 22231209943489 is an apocalyptic number.
It is an amenable number.
2231209943489 is a deficient number, since it is larger than the sum of its proper divisors (1).
2231209943489 is an equidigital number, since it uses as much as digits as its factorization.
2231209943489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 56.
The spelling of 2231209943489 in words is "two trillion, two hundred thirty-one billion, two hundred nine million, nine hundred forty-three thousand, four hundred eighty-nine".
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