Base | Representation |
---|---|
bin | 1100111111001100001… |
… | …1011101010100010100 |
3 | 210022220200201100221020 |
4 | 3033303003131110110 |
5 | 12123423000231400 |
6 | 250300031321140 |
7 | 22056102034641 |
oct | 3176303352424 |
9 | 708820640836 |
10 | 223121102100 |
11 | 86697055446 |
12 | 372aa9801b0 |
13 | 1806a4cca90 |
14 | ab28ad4dc8 |
15 | 5c0d2062a0 |
hex | 33f30dd514 |
223121102100 has 432 divisors, whose sum is σ = 752438715840. Its totient is φ = 50575104000.
The previous prime is 223121102093. The next prime is 223121102107. The reversal of 223121102100 is 1201121322.
It is an interprime number because it is at equal distance from previous prime (223121102093) and next prime (223121102107).
It is a super-3 number, since 3×2231211021003 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 223121102100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (223121102107) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 823324965 + ... + 823325235.
Almost surely, 2223121102100 is an apocalyptic number.
223121102100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 223121102100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (376219357920).
223121102100 is an abundant number, since it is smaller than the sum of its proper divisors (529317613740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
223121102100 is a wasteful number, since it uses less digits than its factorization.
223121102100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 632 (or 354 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 223121102100 its reverse (1201121322), we get a palindrome (224322223422).
It can be divided in two parts, 223121 and 102100, that added together give a triangular number (325221 = T806).
The spelling of 223121102100 in words is "two hundred twenty-three billion, one hundred twenty-one million, one hundred two thousand, one hundred".
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