Base | Representation |
---|---|
bin | 100000011110001001110… |
… | …101011001000100010011 |
3 | 21220022122010201021202101 |
4 | 200132021311121010103 |
5 | 243024402012022043 |
6 | 4425031412501231 |
7 | 320133120212524 |
oct | 40361165310423 |
9 | 7808563637671 |
10 | 2231400501523 |
11 | 790371457596 |
12 | 30056361a817 |
13 | 13256014145b |
14 | 7a000dbc84b |
15 | 3d09cebe24d |
hex | 20789d59113 |
2231400501523 has 2 divisors, whose sum is σ = 2231400501524. Its totient is φ = 2231400501522.
The previous prime is 2231400501511. The next prime is 2231400501593. The reversal of 2231400501523 is 3251050041322.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2231400501523 is a prime.
It is a super-3 number, since 3×22314005015233 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2231400501491 and 2231400501500.
It is not a weakly prime, because it can be changed into another prime (2231400501593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1115700250761 + 1115700250762.
It is an arithmetic number, because the mean of its divisors is an integer number (1115700250762).
Almost surely, 22231400501523 is an apocalyptic number.
2231400501523 is a deficient number, since it is larger than the sum of its proper divisors (1).
2231400501523 is an equidigital number, since it uses as much as digits as its factorization.
2231400501523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 2231400501523 its reverse (3251050041322), we get a palindrome (5482450542845).
The spelling of 2231400501523 in words is "two trillion, two hundred thirty-one billion, four hundred million, five hundred one thousand, five hundred twenty-three".
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