Base | Representation |
---|---|
bin | 10100110011010010… |
… | …100011111001100011 |
3 | 2010122120212211122200 |
4 | 110303102203321203 |
5 | 331220321341011 |
6 | 14132151504243 |
7 | 1420330154466 |
oct | 246322437143 |
9 | 63576784580 |
10 | 22335340131 |
11 | 9521798695 |
12 | 43b4088083 |
13 | 214c4745c0 |
14 | 111c5132dd |
15 | 8aacbd856 |
hex | 5334a3e63 |
22335340131 has 24 divisors (see below), whose sum is σ = 34748903280. Its totient is φ = 13742830656.
The previous prime is 22335340127. The next prime is 22335340171. The reversal of 22335340131 is 13104353322.
22335340131 is a `hidden beast` number, since 223 + 3 + 5 + 3 + 401 + 31 = 666.
It is not a de Polignac number, because 22335340131 - 22 = 22335340127 is a prime.
It is a super-3 number, since 3×223353401313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 22335340095 and 22335340104.
It is not an unprimeable number, because it can be changed into a prime (22335340171) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1503900 + ... + 1518678.
It is an arithmetic number, because the mean of its divisors is an integer number (1447870970).
Almost surely, 222335340131 is an apocalyptic number.
22335340131 is a deficient number, since it is larger than the sum of its proper divisors (12413563149).
22335340131 is a wasteful number, since it uses less digits than its factorization.
22335340131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27715 (or 27712 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 22335340131 its reverse (13104353322), we get a palindrome (35439693453).
The spelling of 22335340131 in words is "twenty-two billion, three hundred thirty-five million, three hundred forty thousand, one hundred thirty-one".
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