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223413431113 is a prime number
BaseRepresentation
bin1101000000010001111…
…0100110101101001001
3210100200001210012221201
43100010132212231021
512130022314243423
6250345033104201
722066251555055
oct3200436465511
9710601705851
10223413431113
118682706a574
1237370858061
13180b5c43122
14ab5586cc65
155c28bec2ad
hex34047a6b49

223413431113 has 2 divisors, whose sum is σ = 223413431114. Its totient is φ = 223413431112.

The previous prime is 223413431107. The next prime is 223413431123. The reversal of 223413431113 is 311134314322.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114495610384 + 108917820729 = 338372^2 + 330027^2 .

It is a cyclic number.

It is not a de Polignac number, because 223413431113 - 29 = 223413430601 is a prime.

It is a super-2 number, since 2×2234134311132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (223413431123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111706715556 + 111706715557.

It is an arithmetic number, because the mean of its divisors is an integer number (111706715557).

Almost surely, 2223413431113 is an apocalyptic number.

It is an amenable number.

223413431113 is a deficient number, since it is larger than the sum of its proper divisors (1).

223413431113 is an equidigital number, since it uses as much as digits as its factorization.

223413431113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 28.

Adding to 223413431113 its reverse (311134314322), we get a palindrome (534547745435).

The spelling of 223413431113 in words is "two hundred twenty-three billion, four hundred thirteen million, four hundred thirty-one thousand, one hundred thirteen".