Base | Representation |
---|---|
bin | 100000100110010010001… |
… | …111001110001101000001 |
3 | 21221011011121111011021212 |
4 | 200212102033032031001 |
5 | 243200242121100324 |
6 | 4433034022455505 |
7 | 320562354640265 |
oct | 40462217161501 |
9 | 7834147434255 |
10 | 2240131425089 |
11 | 7940418756a8 |
12 | 30219b594595 |
13 | 133321c3010c |
14 | 7a5cc7900a5 |
15 | 3d40e74970e |
hex | 209923ce341 |
2240131425089 has 2 divisors, whose sum is σ = 2240131425090. Its totient is φ = 2240131425088.
The previous prime is 2240131425083. The next prime is 2240131425193. The reversal of 2240131425089 is 9805241310422.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1870001550400 + 370129874689 = 1367480^2 + 608383^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2240131425089 is a prime.
It is not a weakly prime, because it can be changed into another prime (2240131425083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1120065712544 + 1120065712545.
It is an arithmetic number, because the mean of its divisors is an integer number (1120065712545).
Almost surely, 22240131425089 is an apocalyptic number.
It is an amenable number.
2240131425089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2240131425089 is an equidigital number, since it uses as much as digits as its factorization.
2240131425089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 138240, while the sum is 41.
The spelling of 2240131425089 in words is "two trillion, two hundred forty billion, one hundred thirty-one million, four hundred twenty-five thousand, eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •