Base | Representation |
---|---|
bin | 1000010110000101… |
… | …1011101111011111 |
3 | 12210010012121022001 |
4 | 2011201123233133 |
5 | 14041433242421 |
6 | 1010141503131 |
7 | 106340553145 |
oct | 20541335737 |
9 | 5703177261 |
10 | 2240134111 |
11 | a4a551a06 |
12 | 526271aa7 |
13 | 299144257 |
14 | 173727595 |
15 | d19e8691 |
hex | 8585bbdf |
2240134111 has 4 divisors (see below), whose sum is σ = 2240257824. Its totient is φ = 2240010400.
The previous prime is 2240134051. The next prime is 2240134129. The reversal of 2240134111 is 1114310422.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1114310422 = 2 ⋅557155211.
It is a cyclic number.
It is not a de Polignac number, because 2240134111 - 213 = 2240125919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2240131111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28810 + ... + 72871.
It is an arithmetic number, because the mean of its divisors is an integer number (560064456).
Almost surely, 22240134111 is an apocalyptic number.
2240134111 is a deficient number, since it is larger than the sum of its proper divisors (123713).
2240134111 is a wasteful number, since it uses less digits than its factorization.
2240134111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123712.
The product of its (nonzero) digits is 192, while the sum is 19.
The square root of 2240134111 is about 47330.0550496194. The cubic root of 2240134111 is about 1308.4526358147.
Adding to 2240134111 its reverse (1114310422), we get a palindrome (3354444533).
The spelling of 2240134111 in words is "two billion, two hundred forty million, one hundred thirty-four thousand, one hundred eleven".
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