Base | Representation |
---|---|
bin | 1000010110000111… |
… | …0011100001101101 |
3 | 12210010101112221021 |
4 | 2011201303201231 |
5 | 14041444402113 |
6 | 1010143534141 |
7 | 106341440161 |
oct | 20541634155 |
9 | 5703345837 |
10 | 2240231533 |
11 | a4a609121 |
12 | 5262ba351 |
13 | 2991796b7 |
14 | 173750ca1 |
15 | d1a1748d |
hex | 8587386d |
2240231533 has 4 divisors (see below), whose sum is σ = 2337632928. Its totient is φ = 2142830140.
The previous prime is 2240231531. The next prime is 2240231557. The reversal of 2240231533 is 3351320422.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2240231533 - 21 = 2240231531 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2240231498 and 2240231507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2240231531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48700663 + ... + 48700708.
It is an arithmetic number, because the mean of its divisors is an integer number (584408232).
Almost surely, 22240231533 is an apocalyptic number.
2240231533 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2240231533 is a deficient number, since it is larger than the sum of its proper divisors (97401395).
2240231533 is an equidigital number, since it uses as much as digits as its factorization.
2240231533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97401394.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 2240231533 is about 47331.0842153441. The cubic root of 2240231533 is about 1308.4716034625.
Adding to 2240231533 its reverse (3351320422), we get a palindrome (5591551955).
Subtracting 2240231533 from its reverse (3351320422), we obtain a square (1111088889 = 333332).
It can be divided in two parts, 22402 and 31533, that added together give a palindrome (53935).
The spelling of 2240231533 in words is "two billion, two hundred forty million, two hundred thirty-one thousand, five hundred thirty-three".
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