Base | Representation |
---|---|
bin | 110010111100000111010011… |
… | …101010101001111100111001 |
3 | 1002101020101012200110001020110 |
4 | 302330013103222221330321 |
5 | 213331030240104113423 |
6 | 2112251255024014533 |
7 | 65121606010254600 |
oct | 6274072352517471 |
9 | 1071211180401213 |
10 | 224033340301113 |
11 | 65425008076712 |
12 | 211631b4461449 |
13 | 980133a786365 |
14 | 3d473b30d6a37 |
15 | 1ad794bdbd193 |
hex | cbc1d3aa9f39 |
224033340301113 has 96 divisors (see below), whose sum is σ = 349235161027200. Its totient is φ = 127374469125120.
The previous prime is 224033340300899. The next prime is 224033340301129. The reversal of 224033340301113 is 311103043330422.
It is not a de Polignac number, because 224033340301113 - 214 = 224033340284729 is a prime.
It is a super-3 number, since 3×2240333403011133 (a number of 44 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (224033340301163) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 57725671933 + ... + 57725675813.
It is an arithmetic number, because the mean of its divisors is an integer number (3637866260700).
Almost surely, 2224033340301113 is an apocalyptic number.
It is an amenable number.
224033340301113 is a deficient number, since it is larger than the sum of its proper divisors (125201820726087).
224033340301113 is a wasteful number, since it uses less digits than its factorization.
224033340301113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6407 (or 6400 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 224033340301113 its reverse (311103043330422), we get a palindrome (535136383631535).
The spelling of 224033340301113 in words is "two hundred twenty-four trillion, thirty-three billion, three hundred forty million, three hundred one thousand, one hundred thirteen".
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