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224043351055 = 5293834034273
BaseRepresentation
bin1101000010101000000…
…1100011110000001111
3210102021222002110122221
43100222001203300033
512132320044213210
6250531334320211
722121001030256
oct3205201436017
9712258073587
10224043351055
118701a6a3767
12375077b9067
13181865b6414
14abb53a379d
155c6417a1da
hex342a063c0f

224043351055 has 16 divisors (see below), whose sum is σ = 278849018880. Its totient is φ = 172602293248.

The previous prime is 224043351031. The next prime is 224043351083. The reversal of 224043351055 is 550153340422.

It is a cyclic number.

It is not a de Polignac number, because 224043351055 - 213 = 224043342863 is a prime.

It is a super-2 number, since 2×2240433510552 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 224043351055.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1961602 + ... + 2072671.

It is an arithmetic number, because the mean of its divisors is an integer number (17428063680).

Almost surely, 2224043351055 is an apocalyptic number.

224043351055 is a deficient number, since it is larger than the sum of its proper divisors (54805667825).

224043351055 is a wasteful number, since it uses less digits than its factorization.

224043351055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4034690.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 224043351055 its reverse (550153340422), we get a palindrome (774196691477).

The spelling of 224043351055 in words is "two hundred twenty-four billion, forty-three million, three hundred fifty-one thousand, fifty-five".

Divisors: 1 5 29 145 383 1915 11107 55535 4034273 20171365 116993917 584969585 1545126559 7725632795 44808670211 224043351055