Base | Representation |
---|---|
bin | 100000100111011001001… |
… | …100111100100111101001 |
3 | 21221021020120210012021112 |
4 | 200213121030330213221 |
5 | 243210211413323423 |
6 | 4433352113120105 |
7 | 320634022516463 |
oct | 40473114744751 |
9 | 7837216705245 |
10 | 2241322011113 |
11 | 7945a2931599 |
12 | 302472259035 |
13 | 1334817a96a3 |
14 | 7a6a294d133 |
15 | 3d47e025a78 |
hex | 209d933c9e9 |
2241322011113 has 2 divisors, whose sum is σ = 2241322011114. Its totient is φ = 2241322011112.
The previous prime is 2241322011107. The next prime is 2241322011151. The reversal of 2241322011113 is 3111102231422.
2241322011113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1249280114944 + 992041896169 = 1117712^2 + 996013^2 .
It is a cyclic number.
It is not a de Polignac number, because 2241322011113 - 222 = 2241317816809 is a prime.
It is not a weakly prime, because it can be changed into another prime (2241322011413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1120661005556 + 1120661005557.
It is an arithmetic number, because the mean of its divisors is an integer number (1120661005557).
Almost surely, 22241322011113 is an apocalyptic number.
It is an amenable number.
2241322011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2241322011113 is an equidigital number, since it uses as much as digits as its factorization.
2241322011113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2241322011113 its reverse (3111102231422), we get a palindrome (5352424242535).
The spelling of 2241322011113 in words is "two trillion, two hundred forty-one billion, three hundred twenty-two million, eleven thousand, one hundred thirteen".
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