Base | Representation |
---|---|
bin | 10101000000011010… |
… | …100100111101011001 |
3 | 2011012221020102112121 |
4 | 111000122210331121 |
5 | 332143204423213 |
6 | 14210055341241 |
7 | 1425642654451 |
oct | 250032447531 |
9 | 64187212477 |
10 | 22555545433 |
11 | 9625021143 |
12 | 4455981821 |
13 | 2185c845b5 |
14 | 113d874d61 |
15 | 8c02b988d |
hex | 5406a4f59 |
22555545433 has 2 divisors, whose sum is σ = 22555545434. Its totient is φ = 22555545432.
The previous prime is 22555545427. The next prime is 22555545473. The reversal of 22555545433 is 33454555522.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13536624409 + 9018921024 = 116347^2 + 94968^2 .
It is a cyclic number.
It is not a de Polignac number, because 22555545433 - 225 = 22521991001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 22555545433.
It is not a weakly prime, because it can be changed into another prime (22555545473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11277772716 + 11277772717.
It is an arithmetic number, because the mean of its divisors is an integer number (11277772717).
Almost surely, 222555545433 is an apocalyptic number.
It is an amenable number.
22555545433 is a deficient number, since it is larger than the sum of its proper divisors (1).
22555545433 is an equidigital number, since it uses as much as digits as its factorization.
22555545433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1800000, while the sum is 43.
The spelling of 22555545433 in words is "twenty-two billion, five hundred fifty-five million, five hundred forty-five thousand, four hundred thirty-three".
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