Base | Representation |
---|---|
bin | 100000111000110101011… |
… | …110100011101000110001 |
3 | 22000001120202210121220121 |
4 | 200320311132203220301 |
5 | 244012040300003213 |
6 | 4450130323010241 |
7 | 322166101015441 |
oct | 40706536435061 |
9 | 8001522717817 |
10 | 2260050000433 |
11 | 7a1533340115 |
12 | 30601a209981 |
13 | 135177799084 |
14 | 7b55bd1c121 |
15 | 3dbc827e88d |
hex | 20e357a3a31 |
2260050000433 has 4 divisors (see below), whose sum is σ = 2260053683440. Its totient is φ = 2260046317428.
The previous prime is 2260050000389. The next prime is 2260050000451. The reversal of 2260050000433 is 3340000500622.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2260050000433 - 213 = 2260049992241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2260050000398 and 2260050000407.
It is not an unprimeable number, because it can be changed into a prime (2260050300433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 674535 + ... + 2230492.
It is an arithmetic number, because the mean of its divisors is an integer number (565013420860).
Almost surely, 22260050000433 is an apocalyptic number.
It is an amenable number.
2260050000433 is a deficient number, since it is larger than the sum of its proper divisors (3683007).
2260050000433 is an equidigital number, since it uses as much as digits as its factorization.
2260050000433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3683006.
The product of its (nonzero) digits is 4320, while the sum is 25.
The spelling of 2260050000433 in words is "two trillion, two hundred sixty billion, fifty million, four hundred thirty-three", and thus it is an aban number.
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