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2265002415433 is a prime number
BaseRepresentation
bin100000111101011100101…
…010100001010101001001
322000112100220122101010101
4200331130222201111021
5244102211104243213
64452305554245401
7322432604604232
oct40753452412511
98015326571111
102265002415433
117a36448a687a
12306b80886861
13135786806854
147b8ab954089
153ddb7e36bdd
hex20f5caa1549

2265002415433 has 2 divisors, whose sum is σ = 2265002415434. Its totient is φ = 2265002415432.

The previous prime is 2265002415427. The next prime is 2265002415449. The reversal of 2265002415433 is 3345142005622.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1213163464969 + 1051838950464 = 1101437^2 + 1025592^2 .

It is a cyclic number.

It is not a de Polignac number, because 2265002415433 - 217 = 2265002284361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2265002415392 and 2265002415401.

It is not a weakly prime, because it can be changed into another prime (2265002415413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1132501207716 + 1132501207717.

It is an arithmetic number, because the mean of its divisors is an integer number (1132501207717).

Almost surely, 22265002415433 is an apocalyptic number.

It is an amenable number.

2265002415433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2265002415433 is an equidigital number, since it uses as much as digits as its factorization.

2265002415433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 37.

The spelling of 2265002415433 in words is "two trillion, two hundred sixty-five billion, two million, four hundred fifteen thousand, four hundred thirty-three".