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2294012438 = 21147006219
BaseRepresentation
bin1000100010111011…
…1101101000010110
312220212120220110122
42020232331220112
514144231344223
61015344351542
7110563532624
oct21056755026
95825526418
102294012438
11a77a01553
125403155b2
132a7359a13
1417a950514
15d65dc5c8
hex88bbda16

2294012438 has 4 divisors (see below), whose sum is σ = 3441018660. Its totient is φ = 1147006218.

The previous prime is 2294012423. The next prime is 2294012447. The reversal of 2294012438 is 8342104922.

2294012438 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×22940124383 (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2294012398 and 2294012407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 573503108 + ... + 573503111.

It is an arithmetic number, because the mean of its divisors is an integer number (860254665).

Almost surely, 22294012438 is an apocalyptic number.

2294012438 is a deficient number, since it is larger than the sum of its proper divisors (1147006222).

2294012438 is a wasteful number, since it uses less digits than its factorization.

2294012438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1147006221.

The product of its (nonzero) digits is 27648, while the sum is 35.

The square root of 2294012438 is about 47895.8499037234. The cubic root of 2294012438 is about 1318.8596744197.

The spelling of 2294012438 in words is "two billion, two hundred ninety-four million, twelve thousand, four hundred thirty-eight".

Divisors: 1 2 1147006219 2294012438