Base | Representation |
---|---|
bin | 100001011110000100100… |
… | …010110001101001100011 |
3 | 22010212210010111121201001 |
4 | 201132010202301221203 |
5 | 300140430442242011 |
6 | 4520341511052431 |
7 | 325112626505032 |
oct | 41360442615143 |
9 | 8125703447631 |
10 | 2300031212131 |
11 | 80748a726234 |
12 | 311917971117 |
13 | 138b799a08a3 |
14 | 7d471bd8719 |
15 | 3ec682a47c1 |
hex | 217848b1a63 |
2300031212131 has 2 divisors, whose sum is σ = 2300031212132. Its totient is φ = 2300031212130.
The previous prime is 2300031212107. The next prime is 2300031212179. The reversal of 2300031212131 is 1312121300032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2300031212131 - 221 = 2300029114979 is a prime.
It is a super-2 number, since 2×23000312121312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2300031212099 and 2300031212108.
It is not a weakly prime, because it can be changed into another prime (2300031218131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1150015606065 + 1150015606066.
It is an arithmetic number, because the mean of its divisors is an integer number (1150015606066).
Almost surely, 22300031212131 is an apocalyptic number.
2300031212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2300031212131 is an equidigital number, since it uses as much as digits as its factorization.
2300031212131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2300031212131 its reverse (1312121300032), we get a palindrome (3612152512163).
The spelling of 2300031212131 in words is "two trillion, three hundred billion, thirty-one million, two hundred twelve thousand, one hundred thirty-one".
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