Base | Representation |
---|---|
bin | 1010011101011100111101… |
… | …10100110001101100001111 |
3 | 10000102222201212201022012010 |
4 | 11032232132310301230033 |
5 | 11003332013403131411 |
6 | 120531023234112303 |
7 | 4562566214200323 |
oct | 516563664615417 |
9 | 100388655638163 |
10 | 23002214505231 |
11 | 7369203470325 |
12 | 26b5b9711b693 |
13 | cab13a853660 |
14 | 5974552c9983 |
15 | 29d518c0e7a6 |
hex | 14eb9ed31b0f |
23002214505231 has 16 divisors (see below), whose sum is σ = 33042520183680. Its totient is φ = 14149337773920.
The previous prime is 23002214505223. The next prime is 23002214505293. The reversal of 23002214505231 is 13250541220032.
It is not a de Polignac number, because 23002214505231 - 23 = 23002214505223 is a prime.
It is a super-2 number, since 2×230022145052312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23002214503231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 122220441 + ... + 122408498.
It is an arithmetic number, because the mean of its divisors is an integer number (2065157511480).
Almost surely, 223002214505231 is an apocalyptic number.
23002214505231 is a deficient number, since it is larger than the sum of its proper divisors (10040305678449).
23002214505231 is a wasteful number, since it uses less digits than its factorization.
23002214505231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244631366.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 23002214505231 its reverse (13250541220032), we get a palindrome (36252755725263).
The spelling of 23002214505231 in words is "twenty-three trillion, two billion, two hundred fourteen million, five hundred five thousand, two hundred thirty-one".
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