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23003134001257 is a prime number
BaseRepresentation
bin1010011101011110101011…
…01000011000000001101001
310000110002002221220112121111
411032233111220120001221
511003340404301020012
6120531254402110321
74562631050605624
oct516572550300151
9100402087815544
1023003134001257
1173696354a92a3
1226b61b304b3a1
13cab2561b4c47
1459750147cdbb
1529d56e7dcba7
hex14ebd5a18069

23003134001257 has 2 divisors, whose sum is σ = 23003134001258. Its totient is φ = 23003134001256.

The previous prime is 23003134001219. The next prime is 23003134001261. The reversal of 23003134001257 is 75210043130032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19974991096921 + 3028142904336 = 4469339^2 + 1740156^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23003134001257 is a prime.

It is not a weakly prime, because it can be changed into another prime (23003134001557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11501567000628 + 11501567000629.

It is an arithmetic number, because the mean of its divisors is an integer number (11501567000629).

Almost surely, 223003134001257 is an apocalyptic number.

It is an amenable number.

23003134001257 is a deficient number, since it is larger than the sum of its proper divisors (1).

23003134001257 is an equidigital number, since it uses as much as digits as its factorization.

23003134001257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 23003134001257 its reverse (75210043130032), we get a palindrome (98213177131289).

The spelling of 23003134001257 in words is "twenty-three trillion, three billion, one hundred thirty-four million, one thousand, two hundred fifty-seven".