Base | Representation |
---|---|
bin | 1010011101011110101011… |
… | …01000011000000001101001 |
3 | 10000110002002221220112121111 |
4 | 11032233111220120001221 |
5 | 11003340404301020012 |
6 | 120531254402110321 |
7 | 4562631050605624 |
oct | 516572550300151 |
9 | 100402087815544 |
10 | 23003134001257 |
11 | 73696354a92a3 |
12 | 26b61b304b3a1 |
13 | cab2561b4c47 |
14 | 59750147cdbb |
15 | 29d56e7dcba7 |
hex | 14ebd5a18069 |
23003134001257 has 2 divisors, whose sum is σ = 23003134001258. Its totient is φ = 23003134001256.
The previous prime is 23003134001219. The next prime is 23003134001261. The reversal of 23003134001257 is 75210043130032.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19974991096921 + 3028142904336 = 4469339^2 + 1740156^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23003134001257 is a prime.
It is not a weakly prime, because it can be changed into another prime (23003134001557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11501567000628 + 11501567000629.
It is an arithmetic number, because the mean of its divisors is an integer number (11501567000629).
Almost surely, 223003134001257 is an apocalyptic number.
It is an amenable number.
23003134001257 is a deficient number, since it is larger than the sum of its proper divisors (1).
23003134001257 is an equidigital number, since it uses as much as digits as its factorization.
23003134001257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 23003134001257 its reverse (75210043130032), we get a palindrome (98213177131289).
The spelling of 23003134001257 in words is "twenty-three trillion, three billion, one hundred thirty-four million, one thousand, two hundred fifty-seven".
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