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230114155703 = 415612540383
BaseRepresentation
bin1101011001001111011…
…1110101110010110111
3210222222001101022001112
43112103313311302313
512232233210440303
6253414000545235
722424305023215
oct3262367656267
9728861338045
10230114155703
1189655495093
123872092221b
1318913243013
14b1cd763cb5
155ebc0ec0d8
hex3593df5cb7

230114155703 has 4 divisors (see below), whose sum is σ = 235726696128. Its totient is φ = 224501615280.

The previous prime is 230114155673. The next prime is 230114155729. The reversal of 230114155703 is 307551411032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 230114155703 - 220 = 230113107127 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 230114155703.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (230114155763) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2806270151 + ... + 2806270232.

It is an arithmetic number, because the mean of its divisors is an integer number (58931674032).

Almost surely, 2230114155703 is an apocalyptic number.

230114155703 is a deficient number, since it is larger than the sum of its proper divisors (5612540425).

230114155703 is an equidigital number, since it uses as much as digits as its factorization.

230114155703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5612540424.

The product of its (nonzero) digits is 12600, while the sum is 32.

Adding to 230114155703 its reverse (307551411032), we get a palindrome (537665566735).

It can be divided in two parts, 23011 and 4155703, that added together give a palindrome (4178714).

The spelling of 230114155703 in words is "two hundred thirty billion, one hundred fourteen million, one hundred fifty-five thousand, seven hundred three".

Divisors: 1 41 5612540383 230114155703