Base | Representation |
---|---|
bin | 110100010100110110010011… |
… | …101110100000111001110010 |
3 | 1010011211022122111212102110020 |
4 | 310110312103232200321302 |
5 | 220130432014002143442 |
6 | 2133240435541344310 |
7 | 66321265500154161 |
oct | 6424662356407162 |
9 | 1104738574772406 |
10 | 230131121131122 |
11 | 67366073410982 |
12 | 21988b52a08096 |
13 | 9b5436b941843 |
14 | 40b85973193d8 |
15 | 1b9138a3389ec |
hex | d14d93ba0e72 |
230131121131122 has 16 divisors (see below), whose sum is σ = 460262865404352. Its totient is φ = 76710269853360.
The previous prime is 230131121131097. The next prime is 230131121131133. The reversal of 230131121131122 is 221131121131032.
230131121131122 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 230131121131092 and 230131121131101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21092953 + ... + 30086124.
It is an arithmetic number, because the mean of its divisors is an integer number (28766429087772).
Almost surely, 2230131121131122 is an apocalyptic number.
230131121131122 is an abundant number, since it is smaller than the sum of its proper divisors (230131744273230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
230131121131122 is a wasteful number, since it uses less digits than its factorization.
230131121131122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51928513.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 230131121131122 its reverse (221131121131032), we get a palindrome (451262242262154).
The spelling of 230131121131122 in words is "two hundred thirty trillion, one hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-one thousand, one hundred twenty-two".
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