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23014110113 is a prime number
BaseRepresentation
bin10101011011101111…
…110111001110100001
32012101220002221000122
4111123233313032201
5334113103010423
614323400130025
71443211464641
oct253357671641
965356087018
1023014110113
11983a957615
124563466915
132229c8c747
141184722521
158ea69a8c8
hex55bbf73a1

23014110113 has 2 divisors, whose sum is σ = 23014110114. Its totient is φ = 23014110112.

The previous prime is 23014110103. The next prime is 23014110121. The reversal of 23014110113 is 31101141032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20029891729 + 2984218384 = 141527^2 + 54628^2 .

It is a cyclic number.

It is not a de Polignac number, because 23014110113 - 220 = 23013061537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23014110091 and 23014110100.

It is not a weakly prime, because it can be changed into another prime (23014110103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11507055056 + 11507055057.

It is an arithmetic number, because the mean of its divisors is an integer number (11507055057).

Almost surely, 223014110113 is an apocalyptic number.

It is an amenable number.

23014110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

23014110113 is an equidigital number, since it uses as much as digits as its factorization.

23014110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 23014110113 its reverse (31101141032), we get a palindrome (54115251145).

The spelling of 23014110113 in words is "twenty-three billion, fourteen million, one hundred ten thousand, one hundred thirteen".