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23014344424147 is a prime number
BaseRepresentation
bin1010011101110011100011…
…10100101111101011010011
310000111011001020022000210021
411032321301310233223103
511004031334133033042
6120540351024244311
74563505623616366
oct516716164575323
9100434036260707
1023014344424147
1173733684989aa
1226b8401470697
13cac3218a5a7b
14597c862860dd
1529d9c8a94867
hex14ee71d2fad3

23014344424147 has 2 divisors, whose sum is σ = 23014344424148. Its totient is φ = 23014344424146.

The previous prime is 23014344424109. The next prime is 23014344424151. The reversal of 23014344424147 is 74142444341032.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23014344424147 - 211 = 23014344422099 is a prime.

It is a super-2 number, since 2×230143444241472 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23014344424187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11507172212073 + 11507172212074.

It is an arithmetic number, because the mean of its divisors is an integer number (11507172212074).

Almost surely, 223014344424147 is an apocalyptic number.

23014344424147 is a deficient number, since it is larger than the sum of its proper divisors (1).

23014344424147 is an equidigital number, since it uses as much as digits as its factorization.

23014344424147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1032192, while the sum is 43.

Adding to 23014344424147 its reverse (74142444341032), we get a palindrome (97156788765179).

The spelling of 23014344424147 in words is "twenty-three trillion, fourteen billion, three hundred forty-four million, four hundred twenty-four thousand, one hundred forty-seven".