Base | Representation |
---|---|
bin | 110100011001000011011110… |
… | …101001111010001100011111 |
3 | 1010012211221122210210012220100 |
4 | 310121003132221322030133 |
5 | 220200200422100232111 |
6 | 2134021315040552143 |
7 | 66351206616545520 |
oct | 6431033651721437 |
9 | 1105757583705810 |
10 | 230420141024031 |
11 | 674676a6627202 |
12 | 21a14b73022653 |
13 | 9b756ab9bc55a |
14 | 40c8574088847 |
15 | 1b98b53a87756 |
hex | d190dea7a31f |
230420141024031 has 24 divisors (see below), whose sum is σ = 380386943000064. Its totient is φ = 131664900681360.
The previous prime is 230420141024027. The next prime is 230420141024089. The reversal of 230420141024031 is 130420141024032.
230420141024031 is a `hidden beast` number, since 2 + 3 + 0 + 4 + 2 + 0 + 1 + 410 + 240 + 3 + 1 = 666.
It is not a de Polignac number, because 230420141024031 - 22 = 230420141024027 is a prime.
It is a super-2 number, since 2×2304201410240312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 230420141023986 and 230420141024004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (230420141014031) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49872291 + ... + 54296276.
It is an arithmetic number, because the mean of its divisors is an integer number (15849455958336).
Almost surely, 2230420141024031 is an apocalyptic number.
230420141024031 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
230420141024031 is a deficient number, since it is larger than the sum of its proper divisors (149966801976033).
230420141024031 is a wasteful number, since it uses less digits than its factorization.
230420141024031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104203691 (or 104203688 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 230420141024031 its reverse (130420141024032), we get a palindrome (360840282048063).
Subtracting from 230420141024031 its reverse (130420141024032), we obtain a palindrome (99999999999999).
The spelling of 230420141024031 in words is "two hundred thirty trillion, four hundred twenty billion, one hundred forty-one million, twenty-four thousand, thirty-one".
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