Base | Representation |
---|---|
bin | 1010011111010010000001… |
… | …10110001101001100001111 |
3 | 10000122222221211222122200102 |
4 | 11033221000312031030033 |
5 | 11010344221424044101 |
6 | 121015535433121315 |
7 | 4600252513664441 |
oct | 517510066151417 |
9 | 100588854878612 |
10 | 23065062331151 |
11 | 7392924421125 |
12 | 27061b685923b |
13 | cb40452b4729 |
14 | 59a4d8092491 |
15 | 29ee9649786b |
hex | 14fa40d8d30f |
23065062331151 has 4 divisors (see below), whose sum is σ = 23065191878400. Its totient is φ = 23064932783904.
The previous prime is 23065062331141. The next prime is 23065062331159. The reversal of 23065062331151 is 15113326056032.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23065062331151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23065062331159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64506191 + ... + 64862768.
It is an arithmetic number, because the mean of its divisors is an integer number (5766297969600).
Almost surely, 223065062331151 is an apocalyptic number.
23065062331151 is a deficient number, since it is larger than the sum of its proper divisors (129547249).
23065062331151 is a wasteful number, since it uses less digits than its factorization.
23065062331151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129547248.
The product of its (nonzero) digits is 97200, while the sum is 38.
Adding to 23065062331151 its reverse (15113326056032), we get a palindrome (38178388387183).
The spelling of 23065062331151 in words is "twenty-three trillion, sixty-five billion, sixty-two million, three hundred thirty-one thousand, one hundred fifty-one".
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