Base | Representation |
---|---|
bin | 1010100000000001110010… |
… | …11110001111000000100011 |
3 | 10000202110011011121110121112 |
4 | 11100000321132033000203 |
5 | 11011304232323113103 |
6 | 121035420333413535 |
7 | 4602151165033004 |
oct | 520007136170043 |
9 | 100673134543545 |
10 | 23090708410403 |
11 | 73a2794a19047 |
12 | 270b17363a2ab |
13 | cb65a162b45a |
14 | 59b84c1791ab |
15 | 2a0997c3acd8 |
hex | 15003978f023 |
23090708410403 has 2 divisors, whose sum is σ = 23090708410404. Its totient is φ = 23090708410402.
The previous prime is 23090708410379. The next prime is 23090708410409. The reversal of 23090708410403 is 30401480709032.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23090708410403 - 26 = 23090708410339 is a prime.
It is a super-3 number, since 3×230907084104033 (a number of 41 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (23090708410409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11545354205201 + 11545354205202.
It is an arithmetic number, because the mean of its divisors is an integer number (11545354205202).
Almost surely, 223090708410403 is an apocalyptic number.
23090708410403 is a deficient number, since it is larger than the sum of its proper divisors (1).
23090708410403 is an equidigital number, since it uses as much as digits as its factorization.
23090708410403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 41.
The spelling of 23090708410403 in words is "twenty-three trillion, ninety billion, seven hundred eight million, four hundred ten thousand, four hundred three".
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