Base | Representation |
---|---|
bin | 1010100000010011010011… |
… | …11011000101011011100011 |
3 | 10000210100102110122101200222 |
4 | 11100021221323011123203 |
5 | 11011433011432324212 |
6 | 121044013344233255 |
7 | 4602633201404321 |
oct | 520115173053343 |
9 | 100710373571628 |
10 | 23100111214307 |
11 | 73a677a61a866 |
12 | 2710b5860b82b |
13 | cb743c69234a |
14 | 59c0a0c84d11 |
15 | 2a0d48481c72 |
hex | 150269ec56e3 |
23100111214307 has 2 divisors, whose sum is σ = 23100111214308. Its totient is φ = 23100111214306.
The previous prime is 23100111214291. The next prime is 23100111214391. The reversal of 23100111214307 is 70341211100132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23100111214307 - 24 = 23100111214291 is a prime.
It is a super-2 number, since 2×231001112143072 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23100111514307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550055607153 + 11550055607154.
It is an arithmetic number, because the mean of its divisors is an integer number (11550055607154).
Almost surely, 223100111214307 is an apocalyptic number.
23100111214307 is a deficient number, since it is larger than the sum of its proper divisors (1).
23100111214307 is an equidigital number, since it uses as much as digits as its factorization.
23100111214307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 23100111214307 its reverse (70341211100132), we get a palindrome (93441322314439).
The spelling of 23100111214307 in words is "twenty-three trillion, one hundred billion, one hundred eleven million, two hundred fourteen thousand, three hundred seven".
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