Base | Representation |
---|---|
bin | 10101100000111000… |
… | …000000101100001111 |
3 | 2012121212222022000120 |
4 | 111200320000230033 |
5 | 334302113211421 |
6 | 14340112000023 |
7 | 1445304611640 |
oct | 254070005417 |
9 | 65555868016 |
10 | 23100132111 |
11 | 9884471181 |
12 | 4588230013 |
13 | 2241a4ab34 |
14 | 1191d156c7 |
15 | 902edd8c6 |
hex | 560e00b0f |
23100132111 has 16 divisors (see below), whose sum is σ = 35457141504. Its totient is φ = 13103722944.
The previous prime is 23100132109. The next prime is 23100132119. The reversal of 23100132111 is 11123100132.
It is a happy number.
It is not a de Polignac number, because 23100132111 - 21 = 23100132109 is a prime.
It is a super-2 number, since 2×231001321112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23100132119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4011745 + ... + 4017498.
It is an arithmetic number, because the mean of its divisors is an integer number (2216071344).
Almost surely, 223100132111 is an apocalyptic number.
23100132111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
23100132111 is a deficient number, since it is larger than the sum of its proper divisors (12357009393).
23100132111 is a wasteful number, since it uses less digits than its factorization.
23100132111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8029390.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 23100132111 its reverse (11123100132), we get a palindrome (34223232243).
It can be divided in two parts, 23100132 and 111, that multiplied together give a palindrome (2564114652).
The spelling of 23100132111 in words is "twenty-three billion, one hundred million, one hundred thirty-two thousand, one hundred eleven".
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