Base | Representation |
---|---|
bin | 10101100000111011… |
… | …010111110000001011 |
3 | 2012121221122001101012 |
4 | 111200323113300023 |
5 | 334302324404003 |
6 | 14340142514135 |
7 | 1445315241065 |
oct | 254073276013 |
9 | 65557561335 |
10 | 23101013003 |
11 | 9884a12a92 |
12 | 458859594b |
13 | 2241c98a83 |
14 | 11920a4735 |
15 | 9031148d8 |
hex | 560ed7c0b |
23101013003 has 2 divisors, whose sum is σ = 23101013004. Its totient is φ = 23101013002.
The previous prime is 23101012997. The next prime is 23101013027. The reversal of 23101013003 is 30031010132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23101013003 - 210 = 23101011979 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (23101013503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550506501 + 11550506502.
It is an arithmetic number, because the mean of its divisors is an integer number (11550506502).
Almost surely, 223101013003 is an apocalyptic number.
23101013003 is a deficient number, since it is larger than the sum of its proper divisors (1).
23101013003 is an equidigital number, since it uses as much as digits as its factorization.
23101013003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 23101013003 its reverse (30031010132), we get a palindrome (53132023135).
The spelling of 23101013003 in words is "twenty-three billion, one hundred one million, thirteen thousand, three".
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