Base | Representation |
---|---|
bin | 110100100001101010111111… |
… | …111100001100101001011001 |
3 | 1010021221120012120002200110011 |
4 | 310201222333330030221121 |
5 | 220234401223242230403 |
6 | 2135153333323521521 |
7 | 66442042631231416 |
oct | 6441527774145131 |
9 | 1107846176080404 |
10 | 231012331211353 |
11 | 6767586354295a |
12 | 21aab8a23892a1 |
13 | 9bb94a5636713 |
14 | 41090b101110d |
15 | 1ba9262e76a6d |
hex | d21abff0ca59 |
231012331211353 has 2 divisors, whose sum is σ = 231012331211354. Its totient is φ = 231012331211352.
The previous prime is 231012331211309. The next prime is 231012331211383. The reversal of 231012331211353 is 353112133210132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 173201734535769 + 57810596675584 = 13160613^2 + 7603328^2 .
It is a cyclic number.
It is not a de Polignac number, because 231012331211353 - 229 = 231011794340441 is a prime.
It is not a weakly prime, because it can be changed into another prime (231012331211383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115506165605676 + 115506165605677.
It is an arithmetic number, because the mean of its divisors is an integer number (115506165605677).
Almost surely, 2231012331211353 is an apocalyptic number.
It is an amenable number.
231012331211353 is a deficient number, since it is larger than the sum of its proper divisors (1).
231012331211353 is an equidigital number, since it uses as much as digits as its factorization.
231012331211353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 231012331211353 its reverse (353112133210132), we get a palindrome (584124464421485).
The spelling of 231012331211353 in words is "two hundred thirty-one trillion, twelve billion, three hundred thirty-one million, two hundred eleven thousand, three hundred fifty-three".
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