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231040113121 is a prime number
BaseRepresentation
bin1101011100101100010…
…0000101100111100001
3211002100120201210211201
43113023010011213201
512241132232104441
6254045515241201
722456250362426
oct3271304054741
9732316653751
10231040113121
1189a90136654
123893aa49201
1318a3002760c
14b27a719d4d
156023554c31
hex35cb1059e1

231040113121 has 2 divisors, whose sum is σ = 231040113122. Its totient is φ = 231040113120.

The previous prime is 231040113091. The next prime is 231040113127. The reversal of 231040113121 is 121311040132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 215007488721 + 16032624400 = 463689^2 + 126620^2 .

It is a cyclic number.

It is not a de Polignac number, because 231040113121 - 213 = 231040104929 is a prime.

It is not a weakly prime, because it can be changed into another prime (231040113127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115520056560 + 115520056561.

It is an arithmetic number, because the mean of its divisors is an integer number (115520056561).

Almost surely, 2231040113121 is an apocalyptic number.

It is an amenable number.

231040113121 is a deficient number, since it is larger than the sum of its proper divisors (1).

231040113121 is an equidigital number, since it uses as much as digits as its factorization.

231040113121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 231040113121 its reverse (121311040132), we get a palindrome (352351153253).

The spelling of 231040113121 in words is "two hundred thirty-one billion, forty million, one hundred thirteen thousand, one hundred twenty-one".