Base | Representation |
---|---|
bin | 100001100111101111001… |
… | …011001111100111011001 |
3 | 22011212120110021210022102 |
4 | 201213233023033213121 |
5 | 300323204443440441 |
6 | 4525215431333145 |
7 | 325631055106226 |
oct | 41475713174731 |
9 | 8155513253272 |
10 | 2310410140121 |
11 | 810926323476 |
12 | 3139338211b5 |
13 | 139b420322b5 |
14 | 7db783d894d |
15 | 4017456269b |
hex | 219ef2cf9d9 |
2310410140121 has 2 divisors, whose sum is σ = 2310410140122. Its totient is φ = 2310410140120.
The previous prime is 2310410140111. The next prime is 2310410140139. The reversal of 2310410140121 is 1210410140132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2139067128025 + 171343012096 = 1462555^2 + 413936^2 .
It is a cyclic number.
It is not a de Polignac number, because 2310410140121 - 26 = 2310410140057 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2310410140093 and 2310410140102.
It is not a weakly prime, because it can be changed into another prime (2310410140111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155205070060 + 1155205070061.
It is an arithmetic number, because the mean of its divisors is an integer number (1155205070061).
Almost surely, 22310410140121 is an apocalyptic number.
It is an amenable number.
2310410140121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2310410140121 is an equidigital number, since it uses as much as digits as its factorization.
2310410140121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 2310410140121 its reverse (1210410140132), we get a palindrome (3520820280253).
The spelling of 2310410140121 in words is "two trillion, three hundred ten billion, four hundred ten million, one hundred forty thousand, one hundred twenty-one".
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