Base | Representation |
---|---|
bin | 10101100001001100… |
… | …010011000010010011 |
3 | 2012122020222110222021 |
4 | 111201030103002103 |
5 | 334304443401011 |
6 | 14340421552311 |
7 | 1445401041241 |
oct | 254114230223 |
9 | 65566873867 |
10 | 23105450131 |
11 | 9887473735 |
12 | 4589b75697 |
13 | 2242b905aa |
14 | 11928db791 |
15 | 9036de471 |
hex | 561313093 |
23105450131 has 16 divisors (see below), whose sum is σ = 24274835200. Its totient is φ = 21963571200.
The previous prime is 23105450129. The next prime is 23105450161. The reversal of 23105450131 is 13105450132.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 23105450131 - 21 = 23105450129 is a prime.
It is a super-2 number, since 2×231054501312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23105450096 and 23105450105.
It is not an unprimeable number, because it can be changed into a prime (23105450161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1446235 + ... + 1462123.
It is an arithmetic number, because the mean of its divisors is an integer number (1517177200).
Almost surely, 223105450131 is an apocalyptic number.
23105450131 is a deficient number, since it is larger than the sum of its proper divisors (1169385069).
23105450131 is a wasteful number, since it uses less digits than its factorization.
23105450131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16750.
The product of its (nonzero) digits is 1800, while the sum is 25.
Subtracting from 23105450131 its reverse (13105450132), we obtain a palindrome (9999999999).
The spelling of 23105450131 in words is "twenty-three billion, one hundred five million, four hundred fifty thousand, one hundred thirty-one".
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