Base | Representation |
---|---|
bin | 10101100001011101… |
… | …101110101110101101 |
3 | 2012122120120122200011 |
4 | 111201131232232231 |
5 | 334312131120023 |
6 | 14341103533221 |
7 | 1445454633433 |
oct | 254135565655 |
9 | 65576518604 |
10 | 23110020013 |
11 | 988a0050a3 |
12 | 458b5ba211 |
13 | 2243b00672 |
14 | 119336ad53 |
15 | 903ce350d |
hex | 56176ebad |
23110020013 has 4 divisors (see below), whose sum is σ = 23348267740. Its totient is φ = 22871772288.
The previous prime is 23110019993. The next prime is 23110020019. The reversal of 23110020013 is 31002001132.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10160035209 + 12949984804 = 100797^2 + 113798^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23110020013 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23110019975 and 23110020002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23110020019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119123718 + ... + 119123911.
It is an arithmetic number, because the mean of its divisors is an integer number (5837066935).
Almost surely, 223110020013 is an apocalyptic number.
It is an amenable number.
23110020013 is a deficient number, since it is larger than the sum of its proper divisors (238247727).
23110020013 is an equidigital number, since it uses as much as digits as its factorization.
23110020013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 238247726.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 23110020013 its reverse (31002001132), we get a palindrome (54112021145).
The spelling of 23110020013 in words is "twenty-three billion, one hundred ten million, twenty thousand, thirteen".
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