Base | Representation |
---|---|
bin | 1010100000100110010011… |
… | …11100111011000011010001 |
3 | 10000211022202101200100220122 |
4 | 11100103021330323003101 |
5 | 11012114404413242114 |
6 | 121052421511520025 |
7 | 4603444036621046 |
oct | 520231174730321 |
9 | 100738671610818 |
10 | 23110312243409 |
11 | 740003485aa26 |
12 | 2712b24989015 |
13 | cb83a6c07341 |
14 | 59c78b9b71cd |
15 | 2a1243cede8e |
hex | 1504c9f3b0d1 |
23110312243409 has 2 divisors, whose sum is σ = 23110312243410. Its totient is φ = 23110312243408.
The previous prime is 23110312243399. The next prime is 23110312243423. The reversal of 23110312243409 is 90434221301132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22893689020225 + 216623223184 = 4784735^2 + 465428^2 .
It is a cyclic number.
It is not a de Polignac number, because 23110312243409 - 28 = 23110312243153 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (23110312243009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555156121704 + 11555156121705.
It is an arithmetic number, because the mean of its divisors is an integer number (11555156121705).
Almost surely, 223110312243409 is an apocalyptic number.
It is an amenable number.
23110312243409 is a deficient number, since it is larger than the sum of its proper divisors (1).
23110312243409 is an equidigital number, since it uses as much as digits as its factorization.
23110312243409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 23110312243409 in words is "twenty-three trillion, one hundred ten billion, three hundred twelve million, two hundred forty-three thousand, four hundred nine".
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