Base | Representation |
---|---|
bin | 1101011100111101001… |
… | …1000000011111011011 |
3 | 211002112112101000000001 |
4 | 3113033103000133123 |
5 | 12241303422230042 |
6 | 254100533353431 |
7 | 22461102135046 |
oct | 3271723003733 |
9 | 732475330001 |
10 | 231111133147 |
11 | 8a017233a94 |
12 | 3895a798877 |
13 | 18a419624bb |
14 | b285d25c5d |
15 | 60298d2bb7 |
hex | 35cf4c07db |
231111133147 has 2 divisors, whose sum is σ = 231111133148. Its totient is φ = 231111133146.
The previous prime is 231111133111. The next prime is 231111133159. The reversal of 231111133147 is 741331111132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231111133147 - 227 = 230976915419 is a prime.
It is not a weakly prime, because it can be changed into another prime (231111133447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115555566573 + 115555566574.
It is an arithmetic number, because the mean of its divisors is an integer number (115555566574).
Almost surely, 2231111133147 is an apocalyptic number.
231111133147 is a deficient number, since it is larger than the sum of its proper divisors (1).
231111133147 is an equidigital number, since it uses as much as digits as its factorization.
231111133147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1512, while the sum is 28.
Adding to 231111133147 its reverse (741331111132), we get a palindrome (972442244279).
The spelling of 231111133147 in words is "two hundred thirty-one billion, one hundred eleven million, one hundred thirty-three thousand, one hundred forty-seven".
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