Base | Representation |
---|---|
bin | 110100100011000111001100… |
… | …001010000001101110101011 |
3 | 1010022022000201021202001100122 |
4 | 310203013030022001232223 |
5 | 220243011441011123201 |
6 | 2135311024101553455 |
7 | 66452145652444313 |
oct | 6443071412015653 |
9 | 1108260637661318 |
10 | 231111320411051 |
11 | 67703840348803 |
12 | 21b06b0971588b |
13 | 9bc591c8c7072 |
14 | 410dbc1b12443 |
15 | 1babb08599e1b |
hex | d231cc281bab |
231111320411051 has 2 divisors, whose sum is σ = 231111320411052. Its totient is φ = 231111320411050.
The previous prime is 231111320411033. The next prime is 231111320411063. The reversal of 231111320411051 is 150114023111132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-231111320411051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 231111320411051.
It is not a weakly prime, because it can be changed into another prime (231111320411011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115555660205525 + 115555660205526.
It is an arithmetic number, because the mean of its divisors is an integer number (115555660205526).
Almost surely, 2231111320411051 is an apocalyptic number.
231111320411051 is a deficient number, since it is larger than the sum of its proper divisors (1).
231111320411051 is an equidigital number, since it uses as much as digits as its factorization.
231111320411051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 26.
Adding to 231111320411051 its reverse (150114023111132), we get a palindrome (381225343522183).
The spelling of 231111320411051 in words is "two hundred thirty-one trillion, one hundred eleven billion, three hundred twenty million, four hundred eleven thousand, fifty-one".
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