Base | Representation |
---|---|
bin | 1010100000101000001100… |
… | …01100110001101000100111 |
3 | 10000211102100211122202022221 |
4 | 11100110012030301220213 |
5 | 11012123442144011403 |
6 | 121053110100333211 |
7 | 4603511062314625 |
oct | 520240614615047 |
9 | 100742324582287 |
10 | 23111323032103 |
11 | 7400503382489 |
12 | 27131673a4207 |
13 | cb8508451067 |
14 | 59c845d32515 |
15 | 2a12a2911dbd |
hex | 150506331a27 |
23111323032103 has 4 divisors (see below), whose sum is σ = 23735953384360. Its totient is φ = 22486692679848.
The previous prime is 23111323032047. The next prime is 23111323032157. The reversal of 23111323032103 is 30123032311132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23111323032103 - 29 = 23111323031591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23111323032163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312315176073 + ... + 312315176146.
It is an arithmetic number, because the mean of its divisors is an integer number (5933988346090).
Almost surely, 223111323032103 is an apocalyptic number.
23111323032103 is a deficient number, since it is larger than the sum of its proper divisors (624630352257).
23111323032103 is an equidigital number, since it uses as much as digits as its factorization.
23111323032103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 624630352256.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 23111323032103 its reverse (30123032311132), we get a palindrome (53234355343235).
The spelling of 23111323032103 in words is "twenty-three trillion, one hundred eleven billion, three hundred twenty-three million, thirty-two thousand, one hundred three".
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