Base | Representation |
---|---|
bin | 10101100001100010… |
… | …101111110011100101 |
3 | 2012122200001110200121 |
4 | 111201202233303211 |
5 | 334313000211031 |
6 | 14341152041541 |
7 | 1445502051556 |
oct | 254142576345 |
9 | 65580043617 |
10 | 23111335141 |
11 | 988a823184 |
12 | 458bb332b1 |
13 | 224417114b |
14 | 11935d032d |
15 | 903ea3011 |
hex | 5618afce5 |
23111335141 has 4 divisors (see below), whose sum is σ = 23675026284. Its totient is φ = 22547644000.
The previous prime is 23111335127. The next prime is 23111335207. The reversal of 23111335141 is 14153311132.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10042044100 + 13069291041 = 100210^2 + 114321^2 .
It is a cyclic number.
It is not a de Polignac number, because 23111335141 - 233 = 14521400549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23111335241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281845510 + ... + 281845591.
It is an arithmetic number, because the mean of its divisors is an integer number (5918756571).
Almost surely, 223111335141 is an apocalyptic number.
It is an amenable number.
23111335141 is a deficient number, since it is larger than the sum of its proper divisors (563691143).
23111335141 is an equidigital number, since it uses as much as digits as its factorization.
23111335141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563691142.
The product of its digits is 1080, while the sum is 25.
Adding to 23111335141 its reverse (14153311132), we get a palindrome (37264646273).
The spelling of 23111335141 in words is "twenty-three billion, one hundred eleven million, three hundred thirty-five thousand, one hundred forty-one".
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