Base | Representation |
---|---|
bin | 11011100011010… |
… | …00001011011001 |
3 | 121002212210000210 |
4 | 31301220023121 |
5 | 433131112213 |
6 | 34533321333 |
7 | 5504301045 |
oct | 1561501331 |
9 | 532783023 |
10 | 231113433 |
11 | 109503a41 |
12 | 65496249 |
13 | 38b5c015 |
14 | 229a1025 |
15 | 154530c3 |
hex | dc682d9 |
231113433 has 32 divisors (see below), whose sum is σ = 332019072. Its totient is φ = 142732800.
The previous prime is 231113431. The next prime is 231113489. The reversal of 231113433 is 334311132.
231113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 231113433 - 21 = 231113431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (231113431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 195103 + ... + 196283.
It is an arithmetic number, because the mean of its divisors is an integer number (10375596).
Almost surely, 2231113433 is an apocalyptic number.
It is an amenable number.
231113433 is a deficient number, since it is larger than the sum of its proper divisors (100905639).
231113433 is a wasteful number, since it uses less digits than its factorization.
231113433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1305.
The product of its digits is 648, while the sum is 21.
The square root of 231113433 is about 15202.4153673027. The cubic root of 231113433 is about 613.6796606257.
Adding to 231113433 its reverse (334311132), we get a palindrome (565424565).
The spelling of 231113433 in words is "two hundred thirty-one million, one hundred thirteen thousand, four hundred thirty-three".
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