Base | Representation |
---|---|
bin | 10101100001100011… |
… | …000010010101011001 |
3 | 2012122200012022210102 |
4 | 111201203002111121 |
5 | 334313010123113 |
6 | 14341153425145 |
7 | 1445502516044 |
oct | 254143022531 |
9 | 65580168712 |
10 | 23111411033 |
11 | 988a8751a7 |
12 | 458bb6b1b5 |
13 | 2244199859 |
14 | 119360dc5b |
15 | 903eba758 |
hex | 5618c2559 |
23111411033 has 2 divisors, whose sum is σ = 23111411034. Its totient is φ = 23111411032.
The previous prime is 23111411021. The next prime is 23111411087. The reversal of 23111411033 is 33011411132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23095792729 + 15618304 = 151973^2 + 3952^2 .
It is a cyclic number.
It is not a de Polignac number, because 23111411033 - 24 = 23111411017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23111410996 and 23111411014.
It is not a weakly prime, because it can be changed into another prime (23111411233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555705516 + 11555705517.
It is an arithmetic number, because the mean of its divisors is an integer number (11555705517).
Almost surely, 223111411033 is an apocalyptic number.
It is an amenable number.
23111411033 is a deficient number, since it is larger than the sum of its proper divisors (1).
23111411033 is an equidigital number, since it uses as much as digits as its factorization.
23111411033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 23111411033 its reverse (33011411132), we get a palindrome (56122822165).
Subtracting 23111411033 from its reverse (33011411132), we obtain a palindrome (9900000099).
The spelling of 23111411033 in words is "twenty-three billion, one hundred eleven million, four hundred eleven thousand, thirty-three".
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